Помогите решить cos12x-sin4x=0
Sin(π/2-12x) -sin4x=0 2sin(π/4-8x)cos(π/4-4x)=0 sin(π/4-8x)=0 π/4-8x=πn -8x=-π/4+πn x=π/32+πn/8 cos(π/4-4x)=0 π/4-4x=π/2+πn -4x=-π/4+π/2+πn -4x=π/4+πn x=-π/16+πn/4