Tg270*sin10cos410-sin1700sin50/sin20sin400+sin70cos500

Question

Tg270*sin10cos410-sin1700sin50/sin20sin400+sin70cos500

Comments

в конце точно сos500

Answer 1

Tg270=---
sin(90-80)cos(360+50)-sin(1620+80)sin50/sin(90-70)sin(360+40)+sin70cos(540-40)=cos80cos50-sin80sin50/cos70sin40+sin70cos40=cos(80+50)/sin(70+40)=cos120/sin110=-0.5/sin110