Решите уравнение cosx/2=-√ 2/2
Cos(x/2) = - √2/2 x/2 = (+ -)arccos(-√2/2) + 2πk, k∈Z x/2 = (+ -)(π - arccos(√2/2)) + 2πk, k∈Z x/2 = (+ -)(π - (π/4)) + 2πk, k∈Z x/2 = (+ -)(3π/4) + 2πk, k∈Z x = (+ -)(3π/2) + 4πk, k∈Z