Помогите. Помогите прошу

Решите задачу:

$\frac{0,35}{ \frac{2}{3}x} = \frac{0.45}{x-10} \\ \frac{0,07}{ \frac{2}{3}x} = \frac{0.09}{x-10} \\ 0,07(x-10)=0.09*\frac{2}{3}x} \\ 0,07x-0.7=0.03*2x \\ 0,07x-0.7=0.06x \\ 0.07x-0.06x=0.7 \\ 0.01x=0.7 \\ x=0.7/0.01=700/1=700$

$\frac{6.8}{x+8}= \frac{2}{x} \\ 6.8x=2(x+8) \\ 6.8x=2x+16 \\ 6.8x-2x=16 \\ 4.8x=16 \\ x=16/4.8=160/48=20/6=10/3=3 \frac{1}{3}$