4*(3-у)= -2*(-8+m)= 4-(-6-t)= 7*(с-2)-10= 10-8*(-3-Х) -2*(х-4)+16(t+2) 7*(5-а)-8 (в+3)=

Question

4*(3-у)=
-2*(-8+m)=
4-(-6-t)=
7*(с-2)-10=
10-8*(-3-Х)
-2*(х-4)+16(t+2)
7*(5-а)-8 (в+3)=

Answer 1

4*(3-y) = 12 - 4y
4- (-6-t) = 4+6+t=10+t
7*(c-2)-10= 7c - 14 -10= 7c -24
10-8*(-3 -x)= 2*(-3-x)= -6 -2x
-2*(x-4) +16*(t+2)= -2x +8 +16t + 32= -2x+16t+40
7*(5-a)-8*(b+3)=35-7a-8b-24=11-7a-8b