Решите уравнение с решением пож прошу срочно

$1) \frac{1}{5} x^{2} =5\Rightarrow x^{2} =25, \\ x_{1} =-5; \\ x_{2} =5 \\ 2)9y ^{2}= \frac{25}{4}\Rightarrow y^{2} = \frac{25}{36} , \\ y_{1} = -\frac{5}{6}; \\ y_{2}= \frac{5}{6} \\ 3)1,44=4 x^{2} \Rightarrow x^{2} = \frac{1,44}{4}\\x_{1} =- \frac{1,2}{2}=-0,6 ; \\ x_{2} =\frac{1,2}{2}=0,6. \\ 4) \frac{5}{7} x^{2} =-3,5+ x^{2} , \\ \frac{5}{7} x^{2}- x^{2} =-3,5 \\ - \frac{2}{7} x^{2} =-3,5 \\ x^{2} = \frac{49}{4} \\ x_{1} =- \frac{7}{2}=-3,5 ; \\ x_{2} =\frac{7}{2}=3,5.$
\ $5)(2y-1) ^{2}=10-4y, \\ 4y ^{2}-4y+1-10+4y=0, \\ 4y^{2}=9=0, \\ y^{2}= \frac{9}{4} , \\ y_{1} =- \frac{3}{2}=-1,5 ; \\ y_{2} =\frac{3}{2}=1,5, \\ 6)(3m-2)(3m+2)=5m ^{2} , \\ 9m ^{2}-4=5m^{2} \\ 4m ^{2}=4 \\ m_{1} =-1 ; \\ m_{2} =1.$