Помогите решить,пожалуйста !
[(1 - tg^2(π/6)] / [(3 + ctg^2(π/3)] + sin(π/6) = [(1 - (1/√3)^2] / [(3 + (1/√3)^2] + 1/2 = (1 - 1/3)/ (3 + 1/3) + 1/2 = 2/10 + 1/2 = 7/10