Срочно !!!!!!! 2sin (4x-Пи/5) = - корень 2

Question

Срочно !!!!!!!

2sin (4x-Пи/5) = - корень 2

Answer 1

Sin(4x-π/5)=-√2/2
4x-π/5=(-1)^n+1*π/4+πn
4x=π/5+(-1)^n+1*π/4+πn
x=π/20+(-1)^n+1*π/16+πn/4