1)x^2-4x>-4 2)(2x-1)^2<4x+61

Question

1)x^2-4x>-4
2)(2x-1)^2<4x+61

Answer 1

Х^2-4x>-4
x^2-4x+4>0
x^2-4x+4=0
по т.Виета
x*x = 4    ⇒   x=2
x+x = 4         x=2
отв.: x∈ (2;+∞)

Comments

(2x-1)^2<4x+61

Answer 2

1)  -4 \\ x^{2} -4x +4>0 \\ D=16-16=0 \\ x> \frac{4}{2} \\ x>2" alt=" x^{2} -4x > -4 \\ x^{2} -4x +4>0 \\ D=16-16=0 \\ x> \frac{4}{2} \\ x>2" align="absmiddle" class="latex-formula">

2)