A)2arcsin √2/2 - 1/2 arctg √3 Б)ctg (arccos 1/2 + arcsin √3/2)

Question

A)2arcsin √2/2 - 1/2 arctg √3
Б)ctg (arccos 1/2 + arcsin √3/2)

Answer 1

A)2arcsin√2/2-1/2arctg√3=2*45°-1/2*60°=90°-30°=60
б) ctg(arccos1/2+arcsin√3/2)=ctg(60°+60°)=ctg120°=-√3/3