Плизк, помогите!!! 25 б даю
У=√-х²+х+2 х²-3 {-х²+х+2≥0 {x²-x-2≤0 {x²-x-2≤0 { х²-3≠0 {x²≠3 {x≠√3=1.73 {x≠-√3=-1.73 x²-x-2≤0 f(x)=x²-x-2 - парабола, ветви направлены вверх Нули функции: х²-х-2=0 Д=1+4*2=9=3² х₁=(1-3)/2=-2/2=-1 х₂=(1+3)/2=4/2=2 + - + ---------- -1 ------- 1.73 -- 2 -------- \\\\\\\\\\ \\\\ х∈[-1; √3)∨(√3;2] D(x)=[-1; √3)∨(√3; 2] - область определения функции
![x \in [-1;\sqrt{3})\cup(\sqrt{3};2]](https://tex.z-dn.net/?f=x+%5Cin+%5B-1%3B%5Csqrt%7B3%7D%29%5Ccup%28%5Csqrt%7B3%7D%3B2%5D "x \in [-1;\sqrt{3})\cup(\sqrt{3};2]")
![D(y)=[-1;\sqrt{3})\cup(\sqrt{3};2]](https://tex.z-dn.net/?f=D%28y%29%3D%5B-1%3B%5Csqrt%7B3%7D%29%5Ccup%28%5Csqrt%7B3%7D%3B2%5D "D(y)=[-1;\sqrt{3})\cup(\sqrt{3};2]")