1)x>0
(2+log(3)x)²+(1+log(3)x)²=1
4+4log(3)x+log²(3)x+1+2log(3)x+log²(3)x=1
2log²(3)x+6log(3)x+4=0
log²(3)x+3log(3)x+2=0
log(3)x=a
a²+3a+2=0
a1+a2=-3 U a1*a2=2
a1=-2⇒log(3)x=-2⇒x=1/9
a2=-1⇒log(3)x=-1⇒x=1/3
2)9-2^x>0 U 3-x>0⇒2^x<9 U x<3⇒x<log(2)9 U x<3⇒x<3<br>log2(9-2^x)=3-x
9-2^x=2^(3-x)
9-2^x-8/2^x=0
2^2x-9*2^x-8=0
2^x=a
a²-9a+8=0
a1+a2=9 U a1*a2=8
a1=1⇒2^x=1⇒x=0
a2=8⇒2^x=8⇒x=3 не удов
Ответ х=0