Chr (Ord ('5')-2))= sqrt (.sqr (35)+ Sqr(12))=

Question

Chr (Ord ('5')-2))=
sqrt (.sqr (35)+ Sqr(12))=

Answer 1

1) ord('5') = 53
ord('5') - 2 = 51
chr(ord('5')-2) = '3'

2) sqr(35) = 1225
sqr(12) = 144
sqr(35)+sqr(12)=1369
sqrt(sqr(35)+sqr(12)) = 37