log2^1/2(x²-3x)=4 ОДЗ x²-3x>0⇒x(x-3)>0
2log2(x²-3x)=log2(16) ____+__0 ___-____3 _+_
log2(x²-3x)²=log2(16)
(x²-3x)²=16
(x²-3x)²-4²=0
(x²-3x-4)(x²-3x+4)=0
x²-3x-4=0 x²-3x+4=0
D=9+16=25 D=9-16=-7 -корней нет
x1=(3+5)/2=4
x2=(3-5)/2=-1