найдите корни уравнения:
б)2x^3+x^2+6x+3=0
г)5x^3-x^2+20x-4=0
1) (2 * X³ - X²) - (6 * X - 3) = 0 X² * (2 * X - 1) - 3 * (2 * X - 1) = 0 (X² - 3) * (2 * X - 1) = 0 2 * (X - √ 3) * (X + √ 3) * (X - 1/2) = 0 X₁ = - √ 3 X₂ = √ 3 X₃ = 1/2
2) x^2(5x+1)-4(5x+1)
(x^2-4)(5x+1)
x^2-4=0 5x+1=0
x^2=4 5x=-1
x= -2,2 x=-1/5