3 1/8 : ( х - 4 7/24) = 17/18 + 1 5/6

Решите задачу:

$3 \frac{1}{8} :(x-4 \frac{7}{24} )= \frac{17}{18} +1 \frac{5}{6} \\ 3 \frac{1}{8} :(x-4 \frac{7}{24} )= \frac{17}{18} +1 \frac{15}{18} \\ 3 \frac{1}{8} :(x-4 \frac{7}{24} )= 2 \frac{7}{9} \\ x-4 \frac{7}{24} =3 \frac{1}{8} :2 \frac{7}{9} \\ x-4 \frac{7}{24} = \frac{25}{8} * \frac{9}{25} \\ x-4 \frac{7}{24} =1 \frac{1}{8} \\ x=1 \frac{1}{8} +4 \frac{7}{24} \\ x=1 \frac{3}{24} +4 \frac{7}{24} \\ x=5 \frac{10}{24} =5 \frac{5}{12}$