Решите уравнение)) (3-х)(х+2)=0
3-х₁=0 х₁=3 х₂+2=0 х₂=-2
3x+6-x2-2x=O -x2+x+6=O x2-x-6=O D= b2-4ac= 1-(4*(-6) ) = 1 + 24 = 25 x1= (1+5)/2=3 x2=(1-5)/2=-2