Помогите пожалуйста решить!
4x^2 -5x -6 = 0
D = b^2 -4ac = -5^2 - 4*4*(-6) = 25 + 96 = 121
VD = V121= 11
X1 = -b+VD/2a = 5+11/2*4 = 16/8 = 2
X2 = -b-VD/2a = 5-11/2*4 = -6/8 = -3/4
OTBET: x = -3/4 v x = 2
D = 5*5 - 4*4*(-6) = 25 +96 = 121
х1 = (5-11) / (2*4) = -6 / 8 = -3/4
х2 = (5+11) / (2*4) = 16/8 = 2
по формулам D=-4*a*c и
х1= (-b-) / 2*a
х2 = (-b+) / 2*a