2/π arcsin(4,5-2x+15x^2 - 6 х^3) = 1/√3 ctg (-46π/3)
4,5-2x+15x^2 - 6 х^3 = t
2/π arcsint = 1/√3 ctg (-46π/3)
2/π arcsint = 1/√3* (-1/√3)
2/π arcsint = -1/3
arcsint = -П/6
t = sin(-П/6)
t = -1/2
4,5-2x+15x^2 - 6 х^3 = -0,5
6x^3 - 15x^2 + 2x - 5 = 0
2x(3x^2 + 1) - 5(3x^2 + 1) = 0
(3x^2 + 1)(2x - 5) = 0
3x^2 + 1 = 0 2x - 5 = 0
3x^2 = -1 х = 2,5
нет решений