Log(3)216=3+3log(3)2=3(1+log(3)2)
log(8)3=1/3log(3)2
log(3)24=1+3log(3)2
log(72)3=1/(2+3log(3)2)
3(1+log(3)2) :1/3log(3)2 - (1+3log(3)2): 1/(2+3log(3)2)=
=9(1+log(3)2)*log(3)2 - (1+3log(3)2)*(2+3log(3)2)=
=9log(3)2+9[log(3)2]²-2-3log(3)2-6log(3)2-9[log(3)2]²=-2