Ррешите пжжжжжжжжжжж плиз

Решите задачу:

$(\frac{4a}{a^2-1}+\frac{a-1}{a+1})*\frac{2a}{a+1}-\frac{a}{a-1}-\frac{a}{a^2-1}=\frac{a^2}{a^2-1}\\\frac{a^2+2a+1}{(a-1)(a+1)}*\frac{2a}{a+1}-\frac{a}{a-1}-\frac{a}{a^2-1}=\frac{a^2}{a^2-1}\\\frac{2a}{a-1}-\frac{a}{a-1}-\frac{a}{a^2-1}=\frac{a^2}{a^2-1}\\\frac{a}{a-1}-\frac{a}{a^2-1}=\frac{a^2}{a^2-1}\\\frac{a^2+a-a}{a^2-1}=\frac{a^2}{a^2-1}\\\frac{a^2}{a^2-1}=\frac{a^2}{a^2-1}$

$(\frac{m-2}{m+2}-\frac{m+2}{m-2}):\frac{8m}{m^2-4}+\frac{1-m}{1-3m}=\frac{2m}{1-3m}\\\frac{m^2-4m+4-m^2-4m-4}{(m+2)(m-2)}*\frac{m^2-4}{8}+\frac{1-m}{1-3m}=\frac{2m}{1-3m}\\\frac{-8m}{m^2-4}*\frac{m^2-4}{8}+\frac{1-m}{1-3m}=\frac{2m}{1-3m}\\-1+\frac{1-m}{1-3m}=\frac{2m}{1-3m}\\\frac{2m}{1-3m}=\frac{2m}{1-3m}$