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Решите задачу:

$4 \frac{1}{7} +12+3 \frac{5}{14} =4 \frac{1*2}{7*2} +12+3 \frac{5}{14}=4 \frac{2}{14} +12+3 \frac{5}{14}= \\ \\ =(4+12+3) + (\frac{2}{14}+\frac{5}{14}) = 19+ \frac{7:7}{14:7} =19 \frac{1}{2} =19,5$

$\frac{3}{2} -1,1- \frac{4}{5} = \frac{3*5}{2*5} -1,1- \frac{4*2}{5*2} = \frac{15}{10} -1,1- \frac{8}{10}= \\ \\ =1,5-1,1-0,8 =0,4-0,8=(-0,4)$

$1 \frac{5}{6} -0,5*(- \frac{10}3} )=1 \frac{5}{6} -( \frac{5}{10} *(- \frac{10}3} ))=1 \frac{5}{6} -(- \frac{5}3} )= \\ \\ = \frac{11}{6} + \frac{5*2}{3*2} = \frac{11}{6} + \frac{10}{6}= \frac{21}{6} =3 \frac{3}{6} =3 \frac{1}{2} =3,5$