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Решите задачу:

$1)3/( x^{1/4} +y ^{1/4} )+3/( x^{1/4} -y ^{1/4})=3(x ^{1/4}-y ^{1/4} + x^{1/4} +y ^{1/4} )/$ $( x^{1/2} -y ^{1/2} )=6 x^{1/4} /( x^{1/2} -y ^{1/2} )$
$2)1/ y^{1/2} -1/ x^{1/2} =( x^{1/2} -y ^{1/2} )/ x^{1/2} y ^{1/2}$
$3)( x^{1/2} -y ^{1/2} )/ x^{1/2} y ^{1/2}:4/ x^{1/4 } y ^{1/2} =$ $( x^{1/2} -y ^{1/2} / x^{1/2} y ^{1/2} * x^{1/4} y^{1/2} /4=( x^{1/2} -y ^{1/2} )/4 x^{1/4}$
$4)6 x^{1/4}/( x^{1/2} -y ^{1/2} )*( x^{1/2} -y ^{1/2} )/4 x^{1/4} =3/2=1,5$