Перейдем к основанию 5
2log(5)x-1/log(5)x-1≥0
(2log²(5)x-log(5)x-1)/log(5)x≥0
log(5)x=a
(2a²-a-1)/a≥0
2a²-a-1=0
D=1+8=9
a1=(1-3)/4=-1/2
a2=(1+3)/4=1
a=0
_ + _ +
-------------------------[-1/2]----------(0)-------------[1]------------------
-1/2≤a<0⇒-1/2≤log(5)x<0⇒1/√5≤x<1<br>a≥1⇒log(5)x≥1⇒x≥5
x∈[1/√5;0) U [5;∞)