Cos^2x-sin(1,5п+x)=0
Решение Cos²x - sin(3π/2 + x) = 0 cos²x + cosx = 0 cosx*(cosx + 1) = 0 1) cosx = 0 x₁ = π/2 + πk, k ∈ Z 2) cosx + 1 = 0 cosx = - 1 x₂ = π + 2πn, n ∈ Z Ответ: x₁ = π/2 + πk, k ∈ Z ; x₂ = π + 2πn, n ∈ Z