1/log(3)(x+1)=1/log(3)(3x²+2x-7)
log(3)(x+1)=log(3)√(3x²+2x-7)
x+1=√(3x²+2x-7)
(x+1)²=3x²+2x-7
3x²+2x-7-x²-2x-1=0
2x²-8=0
2x²=8
x²=4
x=-2
x=2
Проверка
х=-2
1/log(3)(-2+1)
не сущ
х=2
1/log(3)3=1/1=1
1[2log(9)√(12+4-7)]=1/[2log(9)3]=1/(2*1/2)=1/1=1
1=1
Ответ х=2