X(11-6x)-20+(2x-5)^2=0

Question

X(11-6x)-20+(2x-5)^2=0

Answer 1

11x-6x^2-20+4x^2-20x+25=0
4x^2-6x^2+11x-20x+25-20=0
-2x^2-9x+5=0
2x^2+9x-5=0
D=81-4*2*(-5)=81+40=121
D^1/2=11
X1=(-9+11)/4=0,5
X2=(-9-11)/4=-5