найдите ab/c, если ab/(a+b)=1 bc/(b+c)=3 ac/(a+c)=2

Question

найдите ab/c, если

ab/(a+b)=1

bc/(b+c)=3

ac/(a+c)=2

Answer 1

1) AB = A + B

2) BC = 3*(B + C) = 3B + 3C

3) AC = 2A + 2C

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C = (2A + 2C) : A

B = (3B + 3C) : C

A = AB - B

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A*B \ C = (AB - B)*(3B + 3C) \ C \ C = 3AB^2 + 3ABC - 3B^2 - 3BC \ C ^2