решите уравнение: 1) (х+5)^2-(х-1)^2=48 2) (2х-3)^2+(3-4х)(х+5)=82

Question

решите уравнение:

1) (х+5)^2-(х-1)^2=48

2) (2х-3)^2+(3-4х)(х+5)=82

Answer 1

(х+5-х+1)(x+5+x-1)=48

6(2x+4)=48

2x+4=8

2x=4

x=2

2) (2x-3)^2+(3x+15-4x^2-20x)=82

(2x-3)^2-4x^2+17x+15=82

4x^2-12x+9-4x^2+17x+15=82

5x+26=82

5x=56

x=11.2

Answer 2

1) (х+5)^2-(х-1)^2=48

x^2+10x+25-x^2+2x-1-48=0

12x-24=0

x=24/12

x=2

 

2) (2х-3)^2+(3-4х)(х+5)=82 

4x^2-12x+9-17x+15-4x^2-82=0

-29x-58=0

x=-58/29

x=-2