-2sin2x<√3решите пжлст срочно

Question

-2sin2x<√3<br>решите пжлст срочно

Answer 1

-2sin2x<√3<br>sin2x>-√3/2
-π/3 +2πn < 2x < 4π/3+2πn, n∈Z
-π/6 +πn < x < 2π/3 + πn, n∈Z
x∈(-π/6 +πn; 2π/3 + πn), n∈Z