ПОМОГИТЕ!!! Задание 1 , 2 и 6!!!
2) 6а+(4а-7)-(а+3)=6а+4а-7-а-3=9а-10 6) 6b+(5-(b-(3b+2)))=6b+(5-(b-3b-2))=6b+(5-(-2b-2))=6b+(5+2b+2)=6b+(2b+7)=8b+7 1) b/ac=(-1,5)/(2·0,9)=(-1,5)/1,8=-(15·10)/(10·18)=-15/18=-5/6
2) 6а+(4а-7)-(а+3)=24а^2-42а-а-3=24а^2-41а-3 6) 6b+(5-(b-(3b+2)))= 6b+(5-(b-3b-2))=6b+(5-b+3b+2)=6b+5-b+3b+2=8b+7