Пусть x^2 + x = t
t^2 + t - 2 = 0
D = 1 + 4*2 = 9
t1 = ( - 1 + 3)/2 = 1
t2 = ( - 1 - 3)/2 = - 2
x^2 + x = 1
x^2 + x - 1 = 0
D = 1 + 4 = √5
x1 = ( - 1 + √5)/2
x2 = (- 1 - √5)/2
x^2 + x = - 2
x^2 +x + 2 = 0
D = 1 - 4*2 < 0
Нет решений
Ответ
( - 1 + √5)/2
(- 1 - √5)/2