Пж ( а/а+1):(1-3а^2/1-а^2)

Question

Пж ( а/а+1):(1-3а^2/1-а^2)

Answer 1

5a-(3+5a^2)/(a+1)=5a*(a+1)/(a+1)-(3+5a^2)/(a+1)=[5a*(a+1)-(3+5a^2)]/(a+1)=(5a^2+5a-3-5a^2)/(a+1)=(5a-3)/(a+1)
 
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