зная что 4
mаx(x) = 6
max(y) =5
min(x)=4
min(y)=1
min(x+y) = min(x) + min(y)=4+1=5
max(x+y) = max(x) + max(y)=6+5=11
min(x-y) = min(x) - max(y)=4-5=-1
max(x-y) = max(x) - min(y)=6-1=5
min(x*y) = min(x) * min(y)=4*1=4
max(x*y) = max(x) * max(y)=6*5=30
min(x/y) = min(x) / max(y)=4/5=0,8
max(x/y) = max(x) / min(y)=6/1=6
ответ
5 < x+y <11</p>
-1 < x-y < 5
4 < xy < 30
0,8 < x/y < 6