Cos3x+sin5x=0.............
Sin (pi/2 - 3x) + sin 5x = 0 2 sin[(pi/2 + 2x)/2]cos[(pi/2 - 8x)/2] = 0 sin[(pi/2 + 2x)/2] = 0 pi/4 + x = k*pi x = -pi/4 + k*pi cos[(pi/2 - 8x)/2] = 0 pi/4 - 4x = pi/2 + k*pi 4x = -pi/4 - k*pi x = -pi/16 - k*pi/4