3x^2-5x-2=0 реттеу пожалуста
3x^2-5x-2=0 D=25-4*3*(-2)=49 x1=(5+7)/2=12/2=6 x2=(5-7)/2=-2/2=-1
3x²-5x-2 = 0, D = (- 5) ²-4.3. (- 2) = 25 + 24 = 49, √D = √49 = 7, x1 = (5 + 7) / 6 = 12/6 = 2 x 2 = (5-7) / 6 = -2/6 = -1/3