Помогите мне пожалуйста

Решите задачу:

$x=\psi\\=\psi^2+\frac{\psi^2}{\psi^2-2\psi+1}=8 \\\\\\=\dfrac{\psi^2}{\psi^2-2\psi+1}+\dfrac{\psi^2}{1}=8 \\\\\\\dfrac{\psi^2}{\psi^2-2\psi+1}+\dfrac{\psi^2(\psi^2-2\psi+1)}{\psi^2-2\psi+1}=8 \\\\\\\fdrac{\psi^2+\psi^2(\psi^2-2\psi+1)}{\psi^2-2\psi+1}=8 \\\\\\\dfrac{\psi^4-2\psi^3+2\psi^2}{\psi^2-2\psi+1}=8 \\\\\\\dfrac{\psi^4-2\psi^3+2\psi^2}{\psi^2-2\psi+1}(\psi^2-2\psi+1)=8(\psi^2-2\psi+1) \\\psi^4-2\psi^3+2\psi^2=8(\psi^2-2\psi+1) \\\psi^4-2\psi^3+2\psi^2=8\psi^2-16\psi+8 \\\psi^4-2\psi^3+2\psi^2-(8\psi^2-16\psi+8)=0 \\\psi^4-2\psi^3-6\psi^2+16\psi-8=0 \\(\psi-2)^2\(\psi^2+2\psi-2)=0 \\\\\\\boxed{ \dfrac{\psi=2}{\dfrac{\psi=\sqrt{3}-1}{\psi=-1-\sqrt{3}} } } \\\boxed{\textbf{Good day}}$