-x^2 - 4x + 5 >= 0
x^2 + 4x - 5 <= 0<br>D/4 = 4 + 5 = 9
x1 = -2 + 3 = 1=>x<=1<br>x2 = -2 - 3 = -5=>x>=-5 => -5<=x<=1<br>(1 - (-5))/2 = 3 => середина -5 + 3 = -2
(4x - 1)/(3x + 1) >=1 l * (3x + 1) не равном нулю => х не равном - 1/3
4x - 1 >= 3x + 1
x >= 2
{7x - 14 >= 0
{2x>=8
{x >= 2
{x>=4
Ответ: х >= 4