Помогите спс ............
А) = 2x^2 / 5y б) = 2(b+9) / (b+9)^2= 2 / b+9 в) = (y-1)^2 / (1-y)(1+y)= 1-y / 1+y
А) =2х^2/5y б) =2(b+9)/(b+9)^2=2/b+9 в) =(y-1)^2/(1-y)(1+y)= 1-y/1+y