2x²+7x+c=0
D = b² - 4ac = 7² - 4*2*c = 49 - 8c
x1 = (-b+√D)/2a = (-7+√(49-8c))/4
x2 = (-b-√D)/2a = (-7-√(49-8c))/4
Пусть
x1 = -3
-3 = (-7+√(49-8c))/4
-12 = -7 +√(49-8c)
-5 = √(49-8c)
25 = 49 - 8c
25 - 49 = -8c
-24 = -8c
c = 3
x2 = -3
-3 = (-7-√(49-8c))/4
-12 = -7 - √(49-8c)
-5 = -√(49-8c)
25 = 49 - 8c
-24 = -8c
c = 3
Итак, с = 3
2x² + 7x + 3 = 0
D = b² - 4ac = 49 - 4*2*3 = 49 - 24 = 25 = 5²
x1 = (-b+√D)/2a = (-7+5)/4 = -2/4 = -1/2
x2 = (-b-√D)/2a = (-7-5)/4 = -12/4 = -3
Ответ : c = 3, второй корень уравнения = -0,5