Log(12)6=a, log(12)11=b. Найдите log(24)132
Исправлено : log24(132) = log12(132) / log12(24) = log12(12*11) / log12(144/6) = ( log12(12) + log12(11) ) / ( log12(144) - log12(6) ) = ( 1 + b ) / ( log12(12^2) - a ) = ( 1 + b ) / ( 2 log12(12) - a ) = (1 + b ) / ( 2 - a )
Решение задания приложено