Одз: x>0
2 lg lgx = lg(3-2lgx)
lg (lgx)²= lg(3-2lgx)
lg²x = 3-2lgx
lg²x + 2lgx - 3 = 0
Введем замену lgx = t
t² + 2t - 3 = 0
D = 4 - 4*1*(-3) = 16
t1 = (-2+4)/2 = 1
t2 = (-2-4)/2 = -3
Вернемся к замене:
lgx = 1
x = 10
lgx = -3
x = 10⁻³ = 1/1000
10* 1/1000 = 1/100