Помогатите мне пожалуйста уравнение; а) x^2/x-5 + 7x-8/x-5=0 ; б) 4/x -3/x-6=0;...

$1)\frac{x^{2} }{x-5}+\frac{7x-8}{x-5}=0\\\\\frac{x^{2}+7x-8 }{x-5}=0\\\\\left \{ {{x^{2}+7x-8=0 } \atop {x-5\neq0 }} \right.\\\\\left \{ {{(x+8)(x-1)=0} \atop {x\neq5 }} \right.\\\\x+8=0\\\\x_{1}=-8\\\\x-1=0\\\\x_{2}=1$

Ответ : - 8 ; 1

$2)\frac{4}{x}-\frac{3}{x-6}=0\\\\\frac{4x-24-3x}{x(x-6)}=0\\\\\frac{x-24}{x(x-6)}=0\\\\\left \{ {{x-24=0} \atop {x\neq0;x\neq6}} \right.\\\\x-24=0\\\\x=24$

Ответ : 24

$3)\frac{x^{2}-8 }{2x-3}=1\\\\\left \{ {{x^{2}-8=2x-3 } \atop {2x-3\neq 0}} \right.\\\\\left \{ {{x^{2}-2x-5=0 } \atop {x\neq1,5 }} \right.\\\\D=(-2)^{2}-4*(-5)=4+20=24=(2\sqrt{6})^{2}\\\\x_{1}=\frac{2-2\sqrt{6} }{2}=1-\sqrt{6}\\\\x_{2}=\frac{2+2\sqrt{6} }{2}=1+\sqrt{6}$