Помогите пожалуйста

Question

Помогите пожалуйста

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Answer 1

Tg(pi+t)=tg(t)
sin(6pi+t)=sin(t)

Comments

tg(pi+t)=tg(t)sin(6pi+t)=sin(t) \cos(t ) = \sqrt{1 - \sin(t) {}^{2} } \cos(t) = \frac{5}{13} \tan(t) = \frac{ \sin(t) }{ \cos(t) } \tan(t) = \frac{12}{13} \div \frac{5}{13} = \frac{12}{5} = 2.4

Answer 2

tg(pi+t)=tg(t)

sin(6pi+t)=sin(t)

\cos(t ) = \sqrt{1 - \sin(t) {}^{2} }

\cos(t) = \frac{5}{13}

\tan(t) = \frac{ \sin(t) }{ \cos(t) }

\tan(t) = \frac{12}{13} \div \frac{5}{13} = \frac{12}{5} = 2.4