-4\\\\x>-\cfrac{4}{17}\\\\\\ x\in\left(-\cfrac{4}{17};+\infty\right)" alt="\tt3x(x+1)-2x(5x+3)<7x(2-x)+4\\\\3x^2+3x-10x^2-6x<14x-7x^2+4\\\\-7x^2-3x+7x^2-14x<4\\\\-17x<4\\\\17x>-4\\\\x>-\cfrac{4}{17}\\\\\\ x\in\left(-\cfrac{4}{17};+\infty\right)" align="absmiddle" class="latex-formula">