Помогите пожалуйста решите : (x+y=40 (y-x=8 Плиззз

$\displaystyle\tt\left \{ {{x+y=40} \atop{y-x=8~}} \right.\left \{ {{y=40-x} \atop {y-x=8~}} \right. \left \{ {{y=40-x~~~~~} \atop {40-x-x=8}} \right.$

40 - x - x = 8

40 - 2x = 8

2x = 40 - 8

2x = 32

x = 32/2

x = 16

$\displaystyle\tt\left \{ {{x+y=40} \atop {x=16~~~~~}} \right.\left \{ {{16+y=40} \atop {x=16~~~~~~}} \right.$

16 + y = 40

y = 40 - 16

y = 24

$\displaystyle\tt\left \{ {{x=16} \atop {y=24}} \right.$

Ответ: 16; 24.