Ответ:
Объяснение:
t(t+6)=-9<=>t^2+6t+9=0<=>(t+3)^2=0=>\\=>t=-3=>x^2+x-5=-3<=>x^2+x-2=0\\a+b+c=0=>x_1=1;x_2=-2" alt="(x^2+x-5)(x^2+x+1)=-9\\x^2+x-5=t=>t(t+6)=-9<=>t^2+6t+9=0<=>(t+3)^2=0=>\\=>t=-3=>x^2+x-5=-3<=>x^2+x-2=0\\a+b+c=0=>x_1=1;x_2=-2" align="absmiddle" class="latex-formula">