Ответ:
(2;+∞)
Целые значения от 3 до бесконечности
Объяснение:
3+x} \atop {3x-4>x}} \right. \\\\\left \{ {{9x+2-3-x>0} \atop {3x-4-x>0}} \right. \\\left \{ {{8x-1>0} \atop {2x-4>0}} \right. \\\\\left \{ {{8x>1} \atop {2x>4}} \right. \\\\\left \{ {{x>\frac{1}{8} } \atop {x>2}} \right. \\" alt="\left \{ {{9x+2>3+x} \atop {3x-4>x}} \right. \\\\\left \{ {{9x+2-3-x>0} \atop {3x-4-x>0}} \right. \\\left \{ {{8x-1>0} \atop {2x-4>0}} \right. \\\\\left \{ {{8x>1} \atop {2x>4}} \right. \\\\\left \{ {{x>\frac{1}{8} } \atop {x>2}} \right. \\" align="absmiddle" class="latex-formula">
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(2;+∞)
Целые значения от 3 до бесконечности
