Bb
\frac{1}{3}\\\\3x-1<(\frac{1}{4})^2\\\\3x<\frac{17}{16}\\\\x<\frac{17}{48}\\\\x\in (\frac{1}{3},\frac{17}{48})" alt="OOF:\; x>\frac{1}{3}\\\\3x-1<(\frac{1}{4})^2\\\\3x<\frac{17}{16}\\\\x<\frac{17}{48}\\\\x\in (\frac{1}{3},\frac{17}{48})" align="absmiddle" class="latex-formula">