Log (x-5)+log x=log 6 3 3 3

Question

Log (x-5)+log x=log 6
3 3 3

Answer 1

5;\quad \log_3x(x-5)=\log_36\\ x>5;\quad x^2-5x=6\\ x>5;\quad x^2-5x-6=0\\ \boxed{x=6}" alt="\log_3(x-5)+\log_3x=\log_36\\ x>5;\quad \log_3x(x-5)=\log_36\\ x>5;\quad x^2-5x=6\\ x>5;\quad x^2-5x-6=0\\ \boxed{x=6}" align="absmiddle" class="latex-formula">